It looks like a combination of text and index number formats. It looks to be selecting then entirety of row 2, Range(“2:2”) would be another way of expressing this.

My own attempts to use the Workbooks.Open Filename command with a string-variable: NameFile=Filepath/folder/subfoler/filename.extesion failed due to Error in PathOfFile and/or NameOfFile. I checked everything and found that the PathOfFile & NameOfFile, as concatenated strings, were correct.

I also tried it with a Char(34) concatenated in front and at the end of the string, which gave the same error again.
As VBA does not give much explanation about the reason for the error, I started with a search at internet and found your contribution, so I implemented your solution in a macro aaOpenWerkboek() (Werkboek is Dutch).

When running this program, an error message appeared when executing the Application.GetOpenFilename command, as is illustrated in the attached screenshot.
The information which is shown after clicking the Help button does not really help me to find out what causes the error.

One more detail is that I run VBA at a Mac.

I am very interested to hear your conclusion about the problem I encountered. Thank you in advance.